$\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}$

7 0

2 years ago

Name each quadrilateral for which the statement is always true.

sertanlavr [38]

Answer:

rhombus

Step-by-step explanation:

Rhombus has that equiangular and is equilateral but I'm not entirely sure about this...

3 0

2 years ago

El que me lo responda bien le doy 20 puntos mas :v

m_a_m_a [10]

Answer: hehe, I don’t understand spAnIsh

Step-by-step explanation:

8 0

2 years ago

Please give an explanation as well as an answer :)

STatiana [176]

Answer: It is 10 because there are 2 other faces and 8+2=10

Step-by-step explanation:

3 0

2 years ago