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stellarik [79]
4 years ago
11

Given two different prime numbers p and q, find the number of different natural divisors of the number. p^m*q^n

Mathematics
1 answer:
IrinaK [193]4 years ago
7 0
The formula for the number of divisors (d) is
  d = (m+1)(n+1)
where this number includes the values 1 and p^m*q^n

_____
This can be generalized to more or fewer prime factors. Add 1 to each of the exponents and form the product of those values.
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The half-life of Carbon-14 is 5730 years. Suppose a fossil is found with 50% of Carbon-14 as compared to a living sample. How ol
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Answer:

The answer is A.

Step-by-step explanation:

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sleet_krkn [62]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Question 1<br> What is the solution of n² - 49 = 0?<br> 0 +7<br> 07<br> -7<br> O no solution
Sphinxa [80]
Hey there!

This can be written as n^{2}-(7)^{2}

This is in form of \fbox{a^{2}-b^{2}} , it can be expanded as \fbox{(a-b)(a+b)}

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So option 7 , -7 are correct.

Hope this is clear :)
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