“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
Answer:
Q(1,1), N(3,2) A(2,5)
Step-by-step explanation:
Answer:
b, a, c
Step-by-step explanation:'
The side opposite of the smallest angle(50) is always the smallest, which means b is the smallest
Hope this helps!
Answer:
B.
Step-by-step explanation:
1/8 for the first one and second one is 23 times 6
