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natka813 [3]
3 years ago
7

12.56 x 100 please answer!!!!!!!!!!!

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

Answer:

12.56 ^ 100 move the decimal space back 2 spaces because 2 zeros

1,256 is the answer

Step-by-step explanation:

leva [86]3 years ago
3 0

Answer:

its 1,256

Step-by-step explanation:

hope this helps!

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In May, there were 157 people living in Kristin's neighborhood. By August, the population had increased 21%. How many people wer
Archy [21]
It’s B because 21% of 157 is 32.97 which then you would then add with the 157 people already there and get 189.97 and since you cannot have .97 of a person you round it up to 190
8 0
3 years ago
A survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 sen
tatyana61 [14]

Answer:

96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

Step-by-step explanation:

We are given that a survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 seniors, 55 was the  average desired retirement age, with a standard deviation of 3.4 years.

Firstly, the Pivotal quantity for 96% confidence interval for the population mean is given by;

                         P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average desired retirement age = 55 years

            \sigma = sample standard deviation = 3.4 years

            n = sample of seniors = 101

            \mu = true mean retirement age of all college students

<em>Here for constructing 96% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

<u>So, 96% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.114 < t_1_0_0 < 2.114) = 0.96  {As the critical value of t at 100 degree

                                               of freedom are -2.114 & 2.114 with P = 2%}  

P(-2.114 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.114) = 0.96

P( -2.114 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.114 \times {\frac{s}{\sqrt{n} } } ) = 0.96

P( \bar X-2.114 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.114 \times {\frac{s}{\sqrt{n} } } ) = 0.96

<u>96% confidence interval for</u> \mu = [ \bar X-2.114 \times {\frac{s}{\sqrt{n} } } , \bar X+2.114 \times {\frac{s}{\sqrt{n} } } ]

                                           = [ 55-2.114 \times {\frac{3.4}{\sqrt{101} } } , 55+2.114 \times {\frac{3.4}{\sqrt{101} } } ]

                                           = [54.30 , 55.70]

Therefore, 96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

7 0
2 years ago
If the complement of an angle is equal to the supplement of four times the angle, then find the measure of the angle.
lisabon 2012 [21]

Answer:

Step-by-step explanation:

Note that:

Two angles are Complementary when they add up to 90 degrees

Two angles are supplementary when they add up to 180 degrees

Let the angle = x

If the complement of an angle is equal to the supplement of four times the angle, then find the measure of the angle.

90 - x = 180 - 4x

6 0
3 years ago
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

8 0
2 years ago
A scientist finds the distances d that two snakes travel in a time of t seconds. the equation 16t = d represents the relationshi
wlad13 [49]
From the equation given, the time for the black mamba snake to cover distance d, will be d/16 while that for the the rought-scaled snake would be d/1.5.
Assume that the distance covered by both snakes is 200 meters;
Then, 
Time taken by the black mamba is 200/16  = 12.5 seconds, and
Time taken by the rought-scaled snake is 200/1.5 = 133.33 seconds
Clearly the black mamba is faster at 12.5 seconds compared with the rought-scaled snake.
4 0
2 years ago
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