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laila [671]
2 years ago
12

65.2345 x 103= can you please slove it for me! ​

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
4 0

Answer:

6719.1535

Step-by-step explanation:

take 65.2345 times 103.on a calculator and you get 6719.1535

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Mi=5<br> tamirrow is mi bdy<br> 5+2<br> 5+2=6<br> hw ld ore yu tamirrow
JulijaS [17]

Answer:

5+2=7

Step-by-step explanation:

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I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
zhenek [66]

Answer:

use sine or cosine rule

Step-by-step explanation:

that's the answer by using the sine rule

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Emily has 8 coins in her purse totaling 50 cents. The only kinds of coins she has are nickels and dimes. How many nickels does E
makvit [3.9K]
5x + 10y = 50
x + y = 8

x = 8 - y
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She has 6 nickels and 2 dimes
3 0
3 years ago
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The door code to gain access to a top-secret laboratory is 6 digits. The first 3 digits of the code are all odd, and the last 3
WINSTONCH [101]
5 odd numbers and 5 even numbers
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3 0
2 years ago
Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
2 years ago
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