Answer:
nah 1
Step-by-step explanation:
sorry homie later
Answer: $5000; $2000
Step-by-step explanation:
Simolw interest is calculated as: PRT/100
where,
P = principal
R = rate
T = time
Let the money in the 4-yr cd be represented by y.
Since rate = 5.2%
Simple interest = (y × 5.2 × 4)/100
Since he invested $3000 less in a 18-month CD, Let the money in the 18-month CD be represented by (y - $3000).
Then, S.I = [(y - $3000) × 3 × 1.5]/100
The total interest = $1130
We then equate the two simple interest together. This will be:
= (y × 5.2 × 4)/100 + (y - $3000) × 3 × 1.5]/100 = $1130
0.208y + 0.045(y - $3000) = $1130
0.208y + 0.045y - $135 = $1130
0.253y = $1130 + $135
0.253y = $1265
y = $1265/0.253
y = $5000
The money invested in 4-yr CD = $5000
The money invested in the 18-month CD = $5000 - $3000 = $2000
Answer:
(1,2)
(3,3)
(-1/2, 11/2)
Step-by-step explanation:
A system of equations is 2 or more equations for which the same x,y solution exists. We can solve the system in three ways: elimination, substitution, or graphing. Substitution can be used by substituting the value of one variable into the equation.
<u>Pair x=3y-5 and x+y=3</u>
Because x=3y-5, we can substitute 3y-5 into x in x+y=3
x+y=3
(3y-5)+y=3
3y-5+y=3
4y-5=3
4y-5+5=3+5
4y=8
y=2
We now substitute y=2 into x=3y-5.
x=3y-5
x=3(2)-5
x=6-5
x=1
<u>Pair y=x and 3x+3y=18</u>
Because y=x, we can substitute x into y in 3x+3y=18
3x+3y=18
3x+3x=18
6x=18
x=3
We now substitute x=3 into y=x.
y=3.
<u>Pair y=-3x+4 and 5x-y=0</u>
Because y=-3x+4, we can substitute -3x+4 into y in 5x-y=0
5x-y=0
5x-(-3x+4)=0
5x+3x+4=0
8x+4=0
8x=-4
x=-1/2
We now substitute x=-1/2 into y=-3x+4
y=-3x+4
y=-3(-1/2)+4
y=3/2+4
y=11/2
Answer:
The Letter W
Step-by-step explanation:
EHT- The
RTTLEE- Letter
W- W
W is at the end of a rainbow.
Answer:
Ker(T) has basis 
Range(T) has basis
Step-by-step explanation:
If the matrix you wanted to represent is
, then:
.
So, to find ker(T) you must solve the homogenous equation

Using Gauss elimination we obtain the simpler equivalent system

Then, we have that
.
We have that
. On this case we say that the basis is the empty set
.
The range of
is the set of vectors of the form

So,
Where the angle brakets denotes the span.