<span> If all numbers are greater than zero and no repeated numbers exist these are the 5 possible combinations:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6
2 + 3 + 6
2 + 4 + 5.
If one number is allowed to be zero and no repeated numbers exist these are 5 combinations:
</span><span> 0 + 11
1 + 1 + 9
2 + 2 + 7
3 + 3 + 5
4 + 4 + 3
5 + 5 + 1
</span><span>
Hope this helps
</span>
Answer:
Q=33/10-r/10 R=33−10q
Step-by-step explanation:
Espero que sea correcto para ti también puedes hacerme más inteligente si es correcto
The zeros for this function are -2, -1 and a double root of 0.
You can find this by first factoring the polynomial on the inside of the parenthesis. Polynomials like this can be factored by looking for two numbers that multiply to the constant (2) and add up to the second coefficient (3). The numbers 2 and 1 satisfy both of those needs and thus can be used as the numbers in a factoring.
x^2(x^2 + 3x + 2)
x^2(x + 2)(x + 1)
Now to find the zeros, we set each part equal to 0. You may want to split the x^2 into two separate x's for this purpose.
(x)(x)(x + 2)(x + 1)
x = 0
x = 0
x + 2 = 0
x = -2
x + 1 = 0
x = -1
the complete question in the attached figure
step 1
Find the distance of the center of the wall from the left end of the wall
distance=(1/2)*24--------> 12 ft
so
If x is the distance from a painting edge to its corresponding end of the wall, then
|x-12| is the distance from the painting edge to the center of the wall
and
If the painting is centered, then 2|x-12| represents the width of the painting
Since the painting is 10 ft wide,
we have 2|x-12|=10
therefore
the answer is the option B
2|x-12|=10
