Answer:








Step-by-step explanation:
Given



Solving (a): NK
MK is a diagonal and NK is half of the diagonal. So:



Solving (b): JL
JL is a diagonal, and it is twice of NL.



Solving (c): KL
To solve for KL, we consider triangle KNL where:

and





Solving (d - h):
To do this, we consider triangle JKN
-- diagonals bisect one another at right angle
Alternate interior angles are equal. So:

Similarly:


So:







Answer:
-3x+42+9x=6x+42
0x=0
x=0
Step-by-step explanation:
there is no solution
Answer:
18
Step-by-step explanation:
-3(2x-3)
-3x(-6)
-3x-6=18 because the negatives cancel each other out.
Answer: she wants to rent the car for 11 days.
Step-by-step explanation:
Let x represent the number of additional days that Pamela wants to rent the car for.
Customers can pay $40 to rent a compact car for the first day plus $6 for each additional day. This means that the total cost of using this special for x days would be
40 + 6(x - 1) = 40 + 6x - 6
= 34 + 6x
Also, they can rent the same car for $30 the first day and $7 for every additional day beyond that. This means that the total cost of using this special for x days would be
30 + 7(x - 1) = 30 + 7x - 7
= 23 + 7x
Since she found out that the two specials are equivalent for x days, then
34 + 6x = 23 + 7x
7x - 6x = 34 - 23
x = 11
Please read the attached file