I need an operation, sweetheart. Are you looking for a sum, difference, what?
ANSWER
B. x=3,y=2
EXPLANATION
The given equations are

and

We add the two equations to eliminate y.
This implies that that:

Simplify:

Divide both sides by 2.

We put x=3 into any of the equations to find y.
Let us substitute x=3 into equation (1) to get:



Divide both sides by -3 to get;

The solution is therefore x=,y=2.

a) <u>n² + 6 </u>
~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.
- If n = 1, first term = 1² + 6 = 7
- n = 2, second term = 10
- n = 3, third temm = 15
- n = 4, fourth term = 22
- n = 10, tenth term = 106
b) <u>3n²</u>
- If n = 1, first term = 3
- n = 2, second term = 12
- n = 3, third term = 27
- n = 4, fourth term = 48
- n = 10, tenth term = 300
not clear way ..... clear it
No. Not all radical equations have an extraneous solution. <span>However, squaring both sides of an </span>equation<span> can create </span>extraneous solutions.<span>
hope this helps :)</span>