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zalisa [80]
2 years ago
11

What is the decimal equivalent for a centimeter?

Mathematics
1 answer:
bonufazy [111]2 years ago
4 0
The answer is 0.1 an inch is 1 so a centimeter is 0.1
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BARSIC [14]

question 4: the answer is 1/2

question 5: the answer is 58/79

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3 years ago
30 pts with brainliest!
Temka [501]

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PLEASE HELP!!! 20 POINTS!!!! WILL MARK YOU BRAINIEST!!! Two isosceles triangles share the same base. Prove that the medians to t
katovenus [111]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.

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2 years ago
Find the ULE in the triangle below
aivan3 [116]

Where is the triangle?

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2 years ago
To convert 7 m/m to yards per hour around the nearest 10th
raketka [301]
It would be at least 70 yph I am probably sure
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