Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.
i.e. 

We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let
be the sample mean.
Formula : 
Then, the probability that the sample mean is at least $25.00 will be :-

Hence, the likelihood the sample mean is at least $25.00= 0.0170
Answer:
36/60 =6/10
Step-by-step explanation:
36/60 = 0.6
6/10=0.6
Solve for x. The multiplicity of a root is the number of times the root appears.
x=-7 (multiplicity of 1)
x=3 (multiplicity of 2)
x=2-i (multiplicity of 1)
x=2+1 (multiplicity of 1)