Again, a^2+b^2=c^2
c=10
b=9
10 squared is 100
9 squared is 81
100-81=19
The square root of 19, rounded to the nearest hundredth, is 4.36
Across the largest side is going to be largest angle, and across the smallest side -smallest angle.
Sides:
BC = 9 < AB = 13 < CA = 17.
Angles that are across sides: A < C < B.
Answer is d- A C B.
<h3>
Step-by-step explanation:</h3>
<u>Pythagorus theorum:</u>
9² = 3² + YZ²
81 - 9 = YZ²
√72 = YZ
∴YZ= 8.48 ≈ 8.5
<u>Trigonometry:</u>
We have adjacent as 3, and hypotenuse as 9
cos X = 3/9
X= cos∧-1 (3/9) → <em>[cos inversed]</em>
∴X= 70.5°
We have opposite as 3 and hypotenuse as 9
sin Z= 3/9
Z= sin∧-1 (3/9)→<em> [sin inversed]</em>
∴Z= 19.47 ≈ 19.5
16x2=32
21x2=42
32+42=54
the perimeter is 54
I would never know the answer to this question
