Answer:
The hawk reaches the rabbit at t=4.3 sec
Step-by-step explanation:
Let
h ----> is the height in feet
t ----> is the time in seconds
v ---> the initial velocity in feet pr second
s ----- is the starting height
we have

when the hawk reaches the rabbit the value of h is equal to zero
we have


substitute

Solve the quadratic equation by graphing
The solution is t=4.3 sec
see the attached figure
y = A(Bx - C)ⁿ + D
A is a vertical stretch (or shrink if |A| < 1)
B is a vertical shrink (or stretch if |B| < 1)
C is a shift to the right (or left if C is negative) → notice that Bx - C is "-C" so to take the opposite
D is a shift up (or down if D is negative)
when C = -3, it is a shift to the left 3 units
when D = -7, it is a shift down 7 units
Answer: B
Answer:
9
Step-by-step explanation:
18/2=9
Oh wait. I am wrong
Y - y₁ = m(x - x₁)
y - 4 = -2(x - 6)
y - 4 = -2(x) + 2(6)
y - 4 = -2x + 12
+ 4 + 4
y = -2x + 16
The answer is D, (6, 4).
Answer:
∅=6°
Step-by-step explanation:
we have that the distance from the edge of the cliff to the lake is 48 feet, and when the stone is thrown into the lake it collides with the water 5 feet from the base of the cliff so you must find the distance that the stone travels from the edge of the sewer up to 5 feet beyond its base (hypotenuse) and then the angle that forms it (slope)
Hypotenuse (c)
:
Slope ∅
Sin∅ = 5ft/48.25ft = 0.1036
∅=arcsin(0.1036) ≅ 5.9°, but how should we round to the nearest integer
, then:
∅=6°