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3 years ago

How many ways can 7 paintings be lined up in a wall

Mathematics

2 answers:

svetlana [45]3 years ago

6 0

7x6x5x4x3x2x1 = 5040

ehidna [41]3 years ago

5 0

Vertically or horizontally.
Was there answer choices?

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Jose's school spent $1284 on 9 sticksof memory and a new hard drive. The hard drive cost $168. Which is the reasonable estimate

myrzilka [38]

Subtract the cost of the hard drive from the original $1284 and divide the answer you got by the 9 sticks of memory for your answer.

4 0

3 years ago

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The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the trian

Yuri [45]

Not sure, but the areas of a triangle is BH/2 so the dimensions should be 8 and 6 then 10.
8 x 6 = 48
48/2 = 24
Maybe that can help with the equation

4 0

3 years ago

Read 2 more answers

1. What is the sum of 1/9, 2/3, and 5/18? O A. 30 O B. 12/9 O C. 19/18 O D. 4/15

Serhud [2]

Answer:

C. 19/18

Step-by-step explanation:

$\frac{1}{9} + \frac{2}{3} + \frac{5}{18 } = \frac{2}{18} + \frac{12}{18} + \frac{5}{18} = \frac{19}{18}$

So the answer is C. 19/18

6 0

1 year ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

Solve for x: 5x\10=2 is it (a) 1 (b) 4 (c) 5 (d) 20

OleMash [197]

(b) 4

5(4)/10=20/10=2

6 0

3 years ago