Question

If you substitute 12 2x for y in the second equation, how is the resulting equation written in standard form?

Answer 1

The resulting equation written in standard form is 16x² - 22x + 6 = 0.

What is equation in standard form?

Quadratic Equation in Standard Form: ax² + bx + c = 0

a, b and c are known values. a can't be 0.

"x" is the variable or unknown (we don't know it yet).

The "solutions" to the Quadratic Equation are where it is equal to zero.

They are also called "roots", or sometimes "zeros"

We can Factor the Quadratic (find what to multiply to make the Quadratic Equation)

• Or we can Complete the Square

• Or we can use the special Quadratic Formula:

• Quadratic Formula: x = [ -b (+-) √(b² - 4ac) ] / 2a, Just plug in the values of a, b and c, and do the calculations.

Calculation for the given equation-

Now, y=-16x²+24x+6

Substitute, y = 12+2x in y = -16x²+24x+6.

=> 12+2x = -16x²+24x+6

=> 16x²-24x-6+12+2x = 0

=> 16x²-22x+6 = 0

Therefore, the quadratic equation given in the standard form is 16x²-22x+6 = 0.

To know more about the quadratic equation, here

brainly.com/question/1214333

#SPJ4

The complete question is-

The two equations are given below;

Y = 12 + 2x   linear equation

Y = -16x² + 24x + 6  quadratic equation

If you substitute 12 + 2x for y in the second equation how is the resulting equation written in standard form?