I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
Answer:
Im pretty sure the answer is
C) r^2 - 49
Step-by-step explanation:
Answer:
32y^2-32
Step-by-step explanation:
4y^2+4(7y^2-8)
4y^2+28y^2-32
32y^2-32
if you need extra steeps explaining then plz let me know and I will help :)
Answer:
Step-by-step explanation:
(x - 2)(x² + 7x + 4) = x(x² + 7x + 4) - 2*(x² + 7x + 4)
= x*x² + x*7x + 4*x - 2*x² -2* 7x -2* 4
= x³ + 7x² + 4x - 2x² -14x -8
= x³ + <u>7x² - 2x²</u> <u>+ 4x - 14x</u> - 8
= x³ + 5x² - 10x - 8
Combine like terms-- you can combine the k's:

Now you have:

Simply divide both sides by 2.5 to find the value of k: