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Novosadov [1.4K]

2 years ago

15

Write the equation of the line that passes through the points (- 4, - 3) and (3, - 5) . Put your answer in fully reduced slope i

ntercept form, unless it is a vertical or horizontal line
Help me pls:(

1 answer:

bekas [8.4K]2 years ago

6 0

Answer:

(-4, -3) y (3, -5)

{-12 y, 15 y}

-12 y + 15 y = 3 y

(3 y)/2

3 sqrt(41) abs(y)

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The distance between 1 - 10 1/4

Pani-rosa [81]

The distance between 1 - 10 1/4

____________________

1 - 10 1/4 = -9 1/4

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Answer

-9 1/4

9 1/4 (in absolute value)

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1 year ago

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Let r and s be the roots of x^2 - 6x + 2 = 0. Find (r - s)^2.

Sphinxa [80]

Answer: $(r-s)^{2} = 28$

Step-by-step explanation:

$x^{2} -6x+9=-2+9$
$(x-3)^{2}=7$
$(x-3)= -\sqrt{7}$ or $\sqrt{7}$ <-- there's no plus/minus sign.

$(x-3) = -\sqrt{7}$
$x = 3 -\sqrt{7}$ <-- root.

$(x-3) = \sqrt{7}$
$x = 3+\sqrt{7}$ <-- root.

$[(3-\sqrt{7})-(3+\sqrt{7})]^{2}$
$(3-\sqrt{7} -3 - \sqrt{7})^{2}$ <-- don't forget to distribute the negative.
$(-2\sqrt{7})^{2}$
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$28$

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2 years ago

What is an equation of the line that passes through the points (2, -2) and (8, 4)?

WITCHER [35]

Answer:

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Step-by-step explanation:

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2 years ago

Find angle A and angle B..

ExtremeBDS [4]

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

$\tt{\angle{c}=110°}$

and,

$\tt{BC=AC}$

⠀⠀⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

☆Find the $\angle{B} ~and~\angle{A}$

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

Here,

BC =AC

so,

⠀⠀⠀

$\angle{A}=\angle{B}$

we know that,

$\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}$

But $\angle{C}=110°$ (Ģìvéñ)

so..

$\angle{A}+\angle{B}+110°=180°$

$\angle{A}+\angle{A}+110°=180°$

$\because{\angle{A}=\angle{B} }$

$2\angle{A}=180°-110°$

$2\angle{A}=70°$

$\angle{A}=\dfrac{70°}{2}$

$\boxed{\orange{\angle{A}=35°}}$

But...

$\angle{A}=\angle{B}$

soo,

$\boxed{\orange{\angle{B}=35°}}$

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

⠀⠀⠀⠀

$\boxed{\green{\angle{A}=35°}}$

$\boxed{\green{\angle{B}=35°}}$

7 0

2 years ago

Given: Circle k(O) Diameter <br><br>XY tangent WZ, XY = 10, and WZ = 12 .Find: YZ

PtichkaEL [24]

Answer:

<h2>Side YZ is 8 units long.</h2>

Step-by-step explanation:

We can deduct form the graph that segment WO is a radius of the circle and XY is its diameters.

By given, we know that $XY = 10$ , which means $WO=\frac{XY}{2}=\frac{10}{2}=5$ , by radius definition.

An important characteristic of tangents about circles is that the tangent is always is perpendicular to the radius, that means $\angle OWZ = 90\°\\$ and $\triangle OWZ$ is a right triangle, that means we can use Pythagorean's Theorem to find the side YZ.

$OZ^{2} =WZ^{2}+OW^{2}$

Where $OZ$ is the hypothenuse and $WZ$ , $OW$ are legs of the triangle.

Replacing all given values, we have

$OZ^{2}=12^{2}+5^{2}\\OZ=\sqrt{144+25}=\sqrt{169}\\ OZ=13$

However, by sum of segments, we have

$OZ=OY+YZ$ , where $OY=OW=5$ and $OZ=13$

$13=5+YZ\\YZ=13-5\\YZ=8$

Therefore, side YZ is 8 units long.

3 0

2 years ago