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Ray Of Light [21]
3 years ago
12

A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and

constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.
Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval? Select all that apply.

a) There is a 99% chance that a different random sample of 50 runners would have a sample mean run time between 86.05 and 99.38 minutes.
b) We can be 99% confident that the true mean finish time for runners in this race was between 86.05 and 99.38 minutes.
c) Approximately 99% of the runners in the race had a finish time between 86.05 and 99.38 minutes.
d) We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.
Mathematics
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

Option D

Step-by-step explanation:

A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.

Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval?

We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.

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Daniel [21]

Answer:

1. a. Students

2. d. number of U.S. states visited, quantitative

3. a. H o: mu = 16, Ha: mu ≠ 16

4. (7.46,11.50)

Step-by-step explanation:

1. The researcher is interested in finding out the average number of states in US that the students have visited.

The unit that is being observed to arrive at that conclusion is the Students. The observational unit for this study is  a. Students.

2. The variable of interest from the information above is the number of U.S. states visited. The observations recorded for this variable are in numbers which are numeric in nature. This implies that the variable is quantitative in nature.

Therefore, the answe  is d. number of U.S. states visited, quantitative

3. To test whether the average number of states all students at the author’s school have visited,

The null hypothesis (H o) is always given as the negation statement/null of what we wish to test.

So, we wish to test that the average is different from 16. Therefore, the null would be that the average is 16.

Answer  is a. H o: mu = 16, Ha: mu ≠ 16

4. A  95% confidence interval for the average number of states all students at the author’s school have visited can be calculated using the formula:

x  bar + or - 2 √s/n

=9.48 + or - 2 × 7.13/ √50

= (7.46,11.50)

The 95% confidence interval for the average number of states all students at the author’s school have visited is (7.46,11.50). The average falls betw 7.64 and 11.50.

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3 years ago
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zmey [24]

Answer:

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Answer:

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Answer lest edited 3:11 PM Central, 11/24/2020

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