Answer:
A dice of six faces has 5 numbers bigger than 1 (from 2 to 6).
Then, the number Peter is expecting is : 114 x (5/6) = 95 (times)
Hope this helps!
:)
X= -1 t= 7
4(3x-1)=3+8x-11
12x-4=3+8x-11
12x-8x=4+3-11
4x= -4
\4. \4
x= -1
2t+4+5t=6t+11
2t-6t+5t=-4+11
1t=7
\1. \1
t=7
The anwer would be 276,000 because 5 or up u round something lower than 5 it stays the same and the numbers behind it turn into zero's
Hi! It’s me from your other post! Here’s my work for you! It’s been awhile since I’ve done this stuff so I’m really sorry if I get you a bad grade! I just wanted to help out:))
