Answer:
Given:
Two trail maps:
Trail on the first map = 8 cm
Trail on the second map = 6 cm
Scale on first map = 1 cm : 2 km
A) What is the scale factor from the map to the actual trail?
For the first map, the scale factor is 1 cm: 2km. Therefore the actual trail is 8 centimeters * 2 kilometers = 16 km.
The scale factor of the second map is 16 km / 6 cm = 2.67 km : 1 cm
B) The length of the actual trail is 16 kilometers.
Step-by-step explanation:
Answer:
51x^5y^3z^6
Step-by-step explanation:
Please give brainliest
The area of a 2D form is the amount of space within its perimeter. The area of the arrow is 11.25 in².
<h3>What is an area?</h3>
The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.
For the given problem, the image is given below.
The area of the arrow is,
Area = Area of rectangle + Area of triangle
= (1.5 in × 4.5 in) + (0.5×3×3)
= 6.75 in² + 4.5 in²
= 11.25 in²
Hence, the area of the arrow is 11.25 in².
Learn more about the Area:
brainly.com/question/1631786
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1/2in = 16 mi
2 3/4 in without whole numbers [(denominator ×whole) + numerator] / denominator
4×2 = 8 +3 = 11/4
Find common denominator for 1/2 and 11/4 (common D Is 4)
Multiply 1/2 by 2/2
2/4 in = 16 mi divide this by 2
2/4 ×1/2 = 1/4
16 /2 = 8
1/4 = 8
1/4 goes into 11/4 11 times
Multiply 8 times 11
88 miles (D)
End zone to end zone is = length so his scale is 6 in and in real life it is 360 ft
To find scale divide 360 by 6
1in = 60 ft (B)
160 ft wide
(divide 160 by 60 ft ) fraction
160/60 is a fraction now simplify
16/6
Common factors of both numbers is 2
Simplify by 2
8/3
Make into whole number fraction
3 goes into 8 two times (2×3=6)(2 becomes whole number) while there's is 2 left over( 8 -6=2) (becoming the numerator)
2 2/3 in (B)
120 ft long
80 ft wide
24 in is scale of "long"
Divide 120 by 24
120÷24=5
So 5in in scale equals 1ft in real life
To find width in scale divide 80 by 5
80/5= 16in (A)
If you have any trouble understanding feel free to let me know I will try to explain as best as I can :)
Answer:
Step-by-step explanation:
We are given that
Height of man=5 foot
Height of street light=20ft
We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.
ABE and CDE are similar triangle because all right triangles are similar.
Hence, the rate of change of the length of his shadow when he is 25 ft from the street light=
