y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:
5x 1/4
Step-by-step explanation:
Answer:
48 students in the class
Step-by-step explanation:
The ratio of girls to boys is 3 : 5 = 3x : 5x ( x is a multiplier ) , then
5x = 3x + 12 ( 12 more boys than girls )
Subtract 3x from both sides )
2x = 12 ( divide both sides by 2 )
x = 6
Then
number of girls = 3x = 3 × 6 = 18
number of boys = 5x = 5 × 6 = 30
total students in class = 18 + 30 = 48
Square root of 289 = 17 ft
so this rug would not fit the room because one side is 16 ft long.
