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Marat540 [252]
3 years ago
10

. What is the sum of the first 4 multiples of 3?​

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0
The sum of the first 4 multiples of 3 is 30.
First 4 multiples of 3 are: 3, 6, 9, 12
Add them up you get 30.
Hope this helps
KIM [24]3 years ago
6 0
Answer is 30 .I think it’s will help you
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Solve for d.<br><br> 13d + 4 = 43<br><br> A.3<br><br> B.13<br><br> C.39<br><br> D.None of the above
sergejj [24]
Answer is A
Because 43-4=39
39/13=3
6 0
3 years ago
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PLEASE HELP! ITS DUE SOON!!!! I DONT GET THIS!!
o-na [289]

Answer:

d. 50°

Step-by-step explanation:

Since you know one angle and its opposite side, use the law of sines.

sin 36°/11.9 = sin D/15.6

sin D = 15.6 × sin 36° / 11.9

sin D = =0.7705

D = sin^-1 0.7705

D = 50.4°

8 0
2 years ago
6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area
kow [346]
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h

1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6

Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50

3 0
3 years ago
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Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

3 0
3 years ago
Which graph represents the solution of y &gt; x2 + 2?
Vladimir [108]
The questions is asking which one and i say is graph B
4 0
2 years ago
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