2(n+3)= 2n+3<br> explain whys it weong ?

What is the total lifetime cost for a loan had a principal of $5,500, an interest rate of 7.5% compounded monthly, and a duratio

Marizza181 [45]

Answer: the total lifetime cost for the loan is $11616.4

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total cost of the loan at the end of t years.

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount borrowed.

From the information given,

P = $5,500

r = 7.5% = 7.5/100 = 0.075

n = 12 because it was compounded 12 times in a year.

t = 10 years

Therefore,

A = 5500(1 + 0.075/12)^12 × 10

A = 5500(1 + 0.00625)^120

A = 5500(1.00625)^120

A = $11616.4

7 0

3 years ago

A paint that contains 27 % green dye is mixed with a paint that contains 12 % green dye. How many gallons of each must be used t

adelina 88 [10]

Answer:

54 gallons of 26 percent green dye and then 54 gallons of 16 percent green dye

8 0

3 years ago

Please help<br>sina×tga=1/2<br>find cosa <br>

ioda

Step-by-step explanation:

hey you can come in my zoom

4 0

3 years ago

A regression analysis yields the line: y = 12 - 2x

frez [133]

Answer:

x=6

Step-by-step explanation:

7 0

3 years ago

7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many

BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

$_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\$

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

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Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

$_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\$

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

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Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

$_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\$

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

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<h3>Answer: 495</h3>

5 0

3 years ago

2(n+3)= 2n+3 explain whys it weong ?