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viva [34]
3 years ago
13

A large population has a bell-shaped distribution with a mean of 200 and a standard deviation of 40. Which one of the following

intervals would contain approximately 95% of the measurements?
a. (160, 240)
b. (140, 260)
c. (120, 280)
d. (200, 320)
Mathematics
2 answers:
Gwar [14]3 years ago
8 0
The answer would be C
Arturiano [62]3 years ago
3 0
C. (120,280) i believe
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During the construction of a skyscraper, a bolt fell from 400 ft. What was the speed of the bolt when it hit the ground?
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Answer:

160

Step-by-step explanation:

v^2 = 64d

d = 400

v^2 = 64*400

v = sqrt of (64*400) = 160

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3^4 = 3 * 3 * 3 * 3 = 81

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A european business has offered to donate to the Salvation Army, but they are requiring a detailed report on expenditures. Chase
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Answer:

Both processes are correct.

Step-by-step explanation:

Let the mile taken by Chase be 10miles .

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7 0
3 years ago
The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
aleksandr82 [10.1K]

Answer:

a)  P( t > 59 ) = 0.15625

b) P ( 37 < t < 43 ) =0.1875

c) P ( t = 44.74 ) = 0.03125

Step-by-step explanation:

Given:

- The amount of time taken to give the quiz has a random variable X that follows a uniform distribution over the interval [ 32 , 64 ] minutes.

Find:

Find the probability of the following events.

A. The student requires more than 59 minutes to complete the quiz.

B. The student completes the quiz in a time between 37 and 43 minutes.

C. The student completes the quiz in exactly 44.74 minutes.

Solution:

- The probability mass function of a uniform distribution or interval [ a , b ] is given by:

                              pmf f(x) = 1 / ( b - a )

                              f(t) = 1 / ( 64 - 32 )

                              f(t) = 1 / 32

-  The student requires more than 59 minutes to complete the quiz f ( t > 59):

                              CDF F(x) = ( x - a ) / ( b - a )

                              CDF F(t) = ( t - 32 ) / 32

                              P( t > 59 ) = F(64) - F(59)

                              = ( 64 - 32 ) / 32 - ( 59 - 32 ) / 32

                              = 1 - 27/32

                               = 0.15625

- The student completes the quiz in a time between 37 and 43 minutes.

                              P ( 37 < t < 43 ) = F(43) - F(37)

                              = ( 43 - 32 ) / 32 - ( 37 - 32 ) / 32

                              = 3/16

                              = 0.1875

- The student completes the quiz in exactly 44.74 minutes.

The probability for each minute is uniform or constant for the distribution given by pmf:

                               P ( t = 44.74 ) = f(44.74)

                               = 1 / 32

                               = 0.03125

8 0
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Anyway, the value of 5 is 50 and the value of 6 is 6 as in the ones place.
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