Answer:
m∠CEA = 90°
∠CEF is a straight angle
∠AEF is a right angle
Step-by-step explanation:
we know that
BE bisects ∠CEA -----> given problem
so
m∠CEB=m∠BEA
m∠CEA=m∠CEB+m∠BEA
The measure of angle CEA is a right angle -----> m∠CEA=90°
The measure of angle CEF is a straight angle -----> m∠CEF=180°
m∠CEF=m∠CEA+m∠AEF
The measure of angle AEF is a right angle -----> m∠AEF=90°
therefore
The statements that must be true are
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
The answer is a. 145° because a line will always equal 180° so just subtract 180-35 and you get 145°! hope this helped :)
Answer:
Step-by-step explanation:
Mass (m kg) frequency mass (m kg) c.f.
0 < m ≤ 0.1 4 m ≤ 0.1 4
0.1 < m ≤ 0.2 6 m ≤ 0.2 10
0.2 < m ≤ 0.5 58 m ≤ 0.5 68
0.5 < m ≤ 0.8 28 m ≤ 0.8 96
0.8 < m ≤ 1.0 4 m ≤ 1.0 100
Total number of parcels surveyed = cumulative frequency = 100
