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Delvig [45]
3 years ago
11

2tanh1/2x)/(1-tanh21/2x) = sinhx prove

Mathematics
2 answers:
olga55 [171]3 years ago
6 0

Answer:

\[ \cosh^2 x - \sinh^2 x = 1. \]

Step-by-step explanation:

andrey2020 [161]3 years ago
5 0
-24718-9392927289292948-91
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A video rental store has 6,000 movies. One Friday, 3/5 of the movies were rented. How many movies were rented that Friday night?
AleksAgata [21]
6000/ 5 = 1200 x 3 =3600 movies
8 0
4 years ago
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List the factors of 4
il63 [147K]

Answer: 1,2,4,

Step-by-step explanation:

Because....

4 goes into all of these number therefor, these are your factors.

2 × 2 =4

1 × 4 = 4  

* Hopefully this helps:) Mark me the brainliset:) if this is helpful.

8 0
3 years ago
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Please help me with this question I will give brainliest.
Ainat [17]

Answer:

All you need to remember is the rules

Step-by-step explanation:

Let us remember

a to the m power x a to the nth power is = a to the m+n power. (add the exponents)

And

a to the m power ÷ a to the nth power is = a to the m-n power. (subtract the exponents) So

14 to the -4 power x 14 to the 7 power= 14 to the -4+7 which is equal to 14 to the 3rd power

6 0
3 years ago
How to do this and find the max or min points
Veronika [31]
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1

Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1

Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity

So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
8 0
3 years ago
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Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500
Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 500, \pi = \frac{421}{500} = 0.842

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0
4 years ago
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