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lara [203]
3 years ago
10

Find the slope of a line perpendicular to 3x + 5y = 15.

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

B)5/3

Step-by-step explanation:

"3x + 5y = 15."

Rewrite in slope-intercept form.

The slope-intercept form is  

y=mx+b

where  m is the slope and  b  is the y-intercept.

y=mx+b

Subtract  3x  from both sides of the equation.

5y=15−3x

Divide each term by  "5"  and simplify.

5y/5=15/5−3x/5

"5" and "5" cancel each other out

Divide  15  by  5

y=3-3x/5

Reorder  3  and  −3x/5

y=-3x/5+3

Rewrite in slope-intercept form.

y=−3/5x+3

Slope:-3/5

The equation of a perpendicular line to  y=−3x/5+3  must have a slope that is the negative reciprocal of the original slope.

<em>m</em>perpendicular=−1/(−3/5)

Simplify the result.

mperpendicular=5/3

hope this helps!

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