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3 years ago

Find the slope of a line perpendicular to 3x + 5y = 15.

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

8 0

Answer:

B)5/3

Step-by-step explanation:

"3x + 5y = 15."

Rewrite in slope-intercept form.

The slope-intercept form is

y=mx+b

where m is the slope and b is the y-intercept.

y=mx+b

Subtract 3x from both sides of the equation.

5y=15−3x

Divide each term by "5" and simplify.

5y/5=15/5−3x/5

"5" and "5" cancel each other out

Divide 15 by 5

y=3-3x/5

Reorder 3 and −3x/5

y=-3x/5+3

Rewrite in slope-intercept form.

y=−3/5x+3

Slope:-3/5

The equation of a perpendicular line to y=−3x/5+3 must have a slope that is the negative reciprocal of the original slope.

<em>m</em>perpendicular=−1/(−3/5)

Simplify the result.

mperpendicular=5/3

hope this helps!

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Solution:

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<u>To find the product of the expression:</u>

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Arrange the terms with same power.

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Hence option D is the correct answer.

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Answer:

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