Write an equation of the line in slope-intercept form. (Pls answer fast) Y=

Mathematics

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

$y = - \frac{1}{4} x + 3$

You might be interested in

The sales function for a Super Mario Kart Video Game, d(x), after x years is represented by d(x)=30000\left(0.92)^{x}. To the ne

vitfil [10]

Answer:

SO you want me to figure out from year 2 or year4?

Step-by-step explanation:

7 0

2 years ago

Rename numbers using a place value chart

Snowcat [4.5K]

ones tens hundreds thousands millions billions and those are all the place value chart

6 0

3 years ago

2. Solve each given equation and show your work. Tell whether it has one solution, an infinite number of

marin [14]

Answer:

a. infinite solutions, answer is x = 30, identity equation

b. no solution, a contradiction equation

c. no solution, a contradiction equation

Step-by-step explanation:

3 0

3 years ago

Given sec(theta)= 5... find cot(90-theta)

Mumz [18]

$\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 } = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6} 
\\
$

3 0

3 years ago

A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi

nalin [4]

Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$
points (-3,2) and (1,5)
D= $\sqrt{(1-(-3))^{2}+(5-2)^{2}}$
D= $\sqrt{(4)^{2}+(3)^{2}}$
D= $\sqrt{16+9}$
D= $\sqrt{25}$
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle

radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0

3 years ago