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3 years ago

PLEASE HELP ME!!!!!!

Mathematics

1 answer:

White raven [17]3 years ago

8 0

Answer:

This is the graph. The 5 points you can plot can be:

roots: (-6, 0) and (-2, 0)

vertex: (-4, -4)

two other random points to complete the 5 points:

(-5, -3) and (-3, -3)

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Let f(x) = 13 - |2x+ 1|. Find all x for which f(x) less than or equal to 14

Art [367]

Answer:

$x \leqslant -1\: or \: x \geqslant - 1$

Step-by-step explanation:

The given function is

$f(x) = 13 - |2x + 1|$

We want to find all values of x for which:

f(x) is greater than or equal to 14.

This implies;

$13 - |2x + 1| \geqslant 14$

Subtract 13 from both sides;

$- |2x + 1| \geqslant 14 - 13$

$|2x + 1| \geqslant - 1$

By definition of the absolute value function,

$- (2x + 1) \geqslant - 1 \: or \: (2x + 1) \geqslant - 1$

Divide through the first inequality and and reverse the inequality sign:

$2x + 1 \leqslant -1 \: or \: 2x + 1 \geqslant - 1$

$2x \leqslant -1 - 1 \: or \: 2x \geqslant - 1 - 1$

$2x \leqslant -2 \: or \: 2x \geqslant - 2$

$x \leqslant -1\: or \: x \geqslant - 1$

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4 years ago

Hi, i need help please.

Leokris [45]

Answer:

The answer is A.8x+13

Step-by-step explanation:

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3 years ago

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tamaranim1 [39]

Smaller and higher
Is the answer hope it helps if you are still confused ask

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