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4 years ago

What is the translation rule for this translation?

Mathematics

1 answer:

Anna35 [415]4 years ago

7 0

Answer:

T(x,y)->(x-3,y-6)

Step-by-step explanation:

Say we take point E and E1. To move E to E1, we need to move it to the left 3 units, already giving us x-3. Then, we need to find out how far down it moved. by counting the units, we can tell that it moved 6 units down as well, giving us y-6. In the end, we get T(x,y)->(x-3,y-6).

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Constructing a Circle through Three Points Not on a Line

butalik [34]

Answer:

the circle has one point even if it is a concentric circle it will have one central point or it needs more collections of the circle at equidistance

8 0

3 years ago

What is the answer to this problem 3/2 x=−15

fomenos

Answer:

-15×2=-30

30÷3=10

not sure

4 0

3 years ago

Help me!! I need the answer quick!

alukav5142 [94]

Answer:

Step-by-step explanation:

b*h*1/2

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2 years ago

Read 2 more answers

One x-intercept for a parabola is at the point (-2,0).

BARSIC [14]

You can find the x intercept by setting y to 0 and factor the equation.

0=2x^3+3x-2
0=(2x-1)(x+2)

We can make this equation =0 if x is -2 and 1/2.

So the x intercepts are (-2,0) and (0.5,0)

8 0

3 years ago

Give the numerical value of the parameter p in the following binomial distribution scenarioA softball pitcher has a 0.721 probab

Igoryamba

Answer:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

For this case our random variable is given by:

$X \sim Binom(n = 19, p = 0.721)$

For this case we want this probability:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

3 0

4 years ago