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3 years ago

Help help help help help help

Mathematics

1 answer:

SpyIntel [72]3 years ago

7 0

Answer:

R= (-9, -10) S=(-1,-10) T=(-1, -8) U=(-9, -8)

Step-by-step explanation:

There isn't really an explanation it's just reading the points on the graph. Hope this helps!! :)

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Which are equivalent expressions?

ollegr [7]

Answer:

Check Below.

Step-by-step explanation:

x - y = (6 - 5)(y - x) → False

(x - y) (6 - 5) = 1 → False

x- y = (1)(x - y) → True

x - y = 1 + (x - y) → No solution, False

x - y = (6 - 5)(x - y) → True

6 0

2 years ago

A B C D. Which answer put it into an equation

Vesnalui [34]

Answer:

I would believe it to be C. y=4x+10

Step-by-step explanation:

Because you have 4 dollars, and you are adding 10 to it every week and you will want to know what it added to the 4 dollars after a while.

3 0

2 years ago

The length of a rectangle is 5.9 cm more than 3 times the width. If the perimeter of the rectangle is 57.4cm, what are it's dime

navik [9.2K]

Answer:

l = 23 cm and w = 5.7 cm

Step-by-step explanation:

Perimeter = twice the length plus twice the width

let w = width

let l = length

l = 5.9 + 3w

57.4 = 2(5.9 + 3w) + 2w

57.4 = 11.8 + 6w + 2w

57.4 = 11.8 + 8w

45.6 = 8w

w = 5.7

Substitute 5.7 for 'w' to get 'l':

l = 5.9 + 3(5.7)

l = 23

6 0

3 years ago

Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}

algol [13]

Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

$2cos(3x)= -\sqrt{2}$

⇒ $2cos(3x)= -\sqrt{2}$

⇒ $\frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}$

⇒ $cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-2}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-1}{{\sqrt{2}}}$

⇒ $cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})$

⇒ $3x=\pm \frac{\pi}{4}$

⇒ $x=\pm \frac{\pi}{12}$

Cosine General solution is :

$x = \pm cos^{-1}(y)+ 2k\pi$

⇒ $x = \pm \frac{\pi}{12}+ 2k\pi$ , k is any integer .

At k=0,

⇒ $x =\frac{\pi}{12}$ ,

At k=1,

⇒ $x = - \frac{\pi}{12}+ 2\pi$

⇒ $x = \frac{23\pi}{12}$

Therefore , Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

5 0

3 years ago

t hits the square dartboard shown below at a random point. Find the probability that the dart lands in the shaded circular regio

masha68 [24]

Given:

Required:

To find the probability that the dart land will be in the shaded region.

Explanation:

Area of the circle is given by the formula:

$A=\pi r^2$

Where r = radius

Thus the area of the circular region

$\begin{gathered} =(3.14)\times(2)^2 \\ =3.14\times4 \\ =12.56\text{ square in.} \end{gathered}$

The area of the square is given by the formula:

$=(side)^2$

Thus the area of the given square

$\begin{gathered} =(6)^2 \\ =36\text{ square in.} \end{gathered}$

The probability of an event is given by the formula:

$P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}$

The probability that the dart land will be in the shaded region

$=\frac{Area\text{ of the shaded region}}{Area\text{ of the square}}$

Thus probability

$\begin{gathered} P=\frac{12.56}{36} \\ P=0.3488 \\ P=0.349 \end{gathered}$

Final answer:

Thus the probability that the dart land will be in the shaded region is 0.349.

6 0

1 year ago