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3 years ago

Given the following linear function identify the slope in the Y intercept of the function

Mathematics

1 answer:

viva [34]3 years ago

3 0

Answer:

Choice #2

Step-by-step explanation:

Your linear function is in the slope-intercept form of a line, y = mx + b, where m is the value of the slope, and b is the value of the y-intercept. The number in the m position in your equation is 1/6, and thee number in the b position in your equation is 7. So the second choice is the one you want.

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David wants to measure the diameter of his circular pool, but he does not have a tape measure long enough to reach across the po

Kipish [7]

Answer:

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7 0

3 years ago

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

GREYUIT [131]

Answer:

(a) Null Hypothesis, $H_0$ : $\sigma$ = 10 beats per minute

Alternate Hypothesis, $H_A$ : $\sigma\neq$ 10 beats per minute

(b) The value of chi-square test statistics is 35.704.

(c) P-value = 0.4360.

(d) We conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

Step-by-step explanation:

We are given that a simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute.

If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute.

Let $\sigma$ = population standard deviation for the pulse rates of men.

(a) So, Null Hypothesis, $H_0$ : $\sigma$ = 10 beats per minute {means that the pulse rates of men have a standard deviation equal to 10 beats per minute}

Alternate Hypothesis, $H_A$ : $\sigma\neq$ 10 beats per minute {means that the pulse rates of men have a standard deviation different from 10 beats per minute}

The test statistics that will be used here is One-sample chi-square test for standard deviation;

T.S. = $\frac{(n-1)\times s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 10.1 beats per minute

n = sample of men = 36

So, the test statistics = $\frac{(36-1)\times 10.1^{2} }{10^{2} }$ ~ $\chi^{2}__3_5$

= 35.70 4

(b) The value of chi-square test statistics is 35.704.

(c) Also, the P-value of the test statistics is given by;

P-value = P( $\chi^{2}__3_5$ > 35.704) = 0.4360

(d) Since the P-value of our test statistics is more than the level of significance as 0.4360 > 0.10, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.

Therefore, we conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

3 0

4 years ago

1. Find the largest number that divides 15 and 17 without leaving the remainder.

MrMuchimi

Answer:

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Logan earned $8 for each dog he walked last summer. This summer, he raised his fee to $9 per dog. Express the change in Logan’s fees as a percent. Round to the nearest tenth of a percent.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Mean and median of 3,7,2,4,7,5,7,1,8,8.

just olya [345]

Answer;

mean=5.2

median=6

Step-by-step explanation:

5 0

3 years ago