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STALIN [3.7K]
3 years ago
13

Graph shown here is the graph of which of the following rational functions?

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

B) f(x) = 1/x-1

Step-by-step explanation:

You can type it into desmos graphing calculator- hope this helps

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(45/360)2πr=9π/4
Lyrx [107]

Answer:

r=9

Step-by-step explanation:

45/360=1/8

1/8*2=2/8

2/8=1/4

1/4*pi*r=(9pi)/4

Divide both sides by 1/4 (the fours cancel each other out)

Pi*r=9*pi

Pi cancels each other out

R=9

Hope this helps

7 0
4 years ago
The graph of the function f(x) = (x − 3)(x + 1) is shown.
Travka [436]

Answer:

Real values of x where x < -1

Step-by-step explanation:

Above the x-axis, the function is positive.

The function is decreasing when the gradient is negative.

The function has a positive

{x}^{2}

coefficient, therefore the vertex is a local minimum;

This means the gradients are negative before the vertex and positive after it;

To meet the conditions therefore, the function must be before the vertex and above the x-axis;

This will be anywhere before the x-intercept at x = -1;

Hence it is when x < -1.

8 0
3 years ago
Read 2 more answers
Help me plzzz help me plzzz ​
labwork [276]

Answer:

i 25000 cause 250×100 is 25000 ii. 100 cause 10×10 is 100

Step-by-step explanation:

about ii it didnt say anything like the quantity but thats for one tile

3 0
3 years ago
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

                    =0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
3 years ago
4e^2x-6=10<img src="https://tex.z-dn.net/?f=4e%5E2x-6%3D10" id="TexFormula1" title="4e^2x-6=10" alt="4e^2x-6=10" align="absmiddl
Taya2010 [7]
X=4/e^2 or X=0.541341
3 0
3 years ago
Read 2 more answers
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