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dusya [7]
3 years ago
12

Plz help in ASAP I need it I will give you BRAINLEIST whatevrr it is called

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0

Answer:

1.)x≤9

2.)x≥0.5

Step-by-step explanation:

1.)x+6≤15

x+6-6≤15-6

x≤9

2.)x+1.5≥2

x+1.5-1.5≥2-1.5

x≥0.5

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Find the circumference and the area of a circle with radius 4 cm <br><br> Please help!
Alexus [3.1K]
Circumference: 2 * pi * r
pi = 3.14, r = 4
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3.14 * 4^2 = 50.24
Area: 50.24 cm^2
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What is the product of – 7.2 x -3?
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The answer would be -21.6
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Which of the following is a factor of 2x3 – 2?
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ASAP PLS!! i attached a link with a screenshot of the question. please give step by step!!!!! will mark brainliest :)
emmainna [20.7K]

Answer:

I found two different solutions. Hope one of them help!

1. x = -1/3 = -0.333

2. x = 5/2 = 2.500

Step-by-step explanation:

13 ± √ 289

  x  =    ——————

                     12

Can  √ 289 be simplified ?

Yes!   The prime factorization of  289   is

  17•17

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 289   =  √ 17•17   =

               ±  17 • √ 1   =

               ±  17

So now we are looking at:

          x  =  ( 13 ± 17) / 12

Two real solutions:

x =(13+√289)/12=(13+17)/12= 2.500

or

x =(13-√289)/12=(13-17)/12= -0.333

Two solutions were found :

x = -1/3 = -0.333

x = 5/2 = 2.500

7 0
3 years ago
Help center of circle
Lelu [443]

Answer:

Center = (7, - 5)

Radius = 3

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  + 14x - 10y + 65 = 0 \\  {x}^{2}  + 14x +  {y}^{2}  - 10 + 65 = 0 \\ ( {x}^{2}  + 14x +  {7}^{2})  -  {7}^{2}  +  ({y}^{2}  - 10y +  {5}^{2})  \\-  {5}^{2}  + 65 = 0 \\ (x + 7)^{2}  + (y - 5)^{2}  - 49 - 25 + 65 = 0 \\  (x + 7)^{2}  + (y - 5)^{2}  - 49  + 40= 0 \\   (x + 7)^{2}  + (y - 5)^{2}  - 9= 0 \\   (x + 7)^{2}  + (y - 5)^{2}   =  9 \\  (x + 7)^{2}  + (y - 5)^{2}   =   {3}^{2}  \\  equating \: it \: with \: \\ (x  -  h)^{2}  + (y - k)^{2}   =   {r}^{2}  \\  - h = 7 \implies \: h =  - 7 \\  - k =  - 5 \implies \: k = 5 \\ center = ( - h, \:  - k)  = (7, \:  \:  - 5) \\  \\ radius \: r = 3

7 0
4 years ago
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