Pls guys i need help fast D:<br><br> √1024<br><br> √10000<br><br> √1296

Rashad compiled a list of fixed expenses and noted his total expenses for last month.

Digiron [165]

The equation that represents the variable expences for the february is

x+ $1943.48 = $3,291.74

The linear equation is an equation where highest degree of the variables is 1.

As we know Total expenses include fixed as well as variable expenses.

Total Expenses = Variable Expenses +Fixed Expenses

⇒ Variable Expenses = Total Expenses - Fixes Expenses

Hence to Determine variable expenses Rashad needs we have to subtract his fixed expenses from his total expenses for the month.

Here, given that all February fixed expenses amount are

For rent, expenses are $1,150.00

For car loan expenses are $348.00

For internet, expenses are $46.14

For a student loan, expenses are $399.34

So the total amount of fixed expances are= rent expences+ car loan expences+ internet expences+ student loan expences = $1150+ $348+ $46.14+ $399.34 =$1943.48

Given, The total February expanses are $3,291.74.

Let;s assume the variable expenses is x

As we know

Total Expenses = Variable Expenses +Fixed Expenses

Then the linear equation will be

⇒ x+ $1943.48 = $3,291.74

solving for x i.e. Variable Expenses = $3,291.74-$1943.48

⇒ Variable Expenses = $1348.26

Therefore The equation that represents the variable expences for the february is x+ $1943.48 = $3,291.74

Learn more about the linear equation

here: brainly.com/question/2030026

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7 0

2 years ago

What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7

cestrela7 [59]

Answer:

The solution is x =2 for the given equation $\sqrt{9x+7} +\sqrt{2x}=7$

Step-by-step explanation:

We need to find the solution for x in the given equation.

$\sqrt{9x+7} +\sqrt{2x}=7$

Solving:

Subtract $\sqrt{2x}$ from both sides

$\sqrt{9x+7} =7-\sqrt{2x}$

Taking square on both sides

$(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764$