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spin [16.1K]
3 years ago
5

Express 2³a²b in factor form

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

In factor form, the answer is ---> <u>8a^2b </u>

Step-by-step explanation:

2³a²b

= (2^3) (a^2) b

= 8a^2b

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How many solutions does 7z+7=7z have
madreJ [45]

Answer:

no solution

Step-by-step explanation:

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3 years ago
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On a coordinate grid, point P is at (4, 3) and point R is at (−2, −5). Points Q and S are a reflection of both points across the
Aliun [14]
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8 0
3 years ago
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Nostrana [21]
Okay I am not 100% sure because that is an extremely confusing question. But here is what I got.

(A) 2c² = 2bc + ac/2     Given

(B) 4c² = 2bc + ac        Multiplication and Distribution

(C) 4c = 4b + a            Division and Distribution

(D) 4c - a + 4b             Subtraction

(E) 4b = 4c - a              Symmetric
6 0
4 years ago
Plz help me!!
ozzi

Answer:

You should circle:

15, 17, 19, 24, 25, 26, 28

Step-by-step explanation:

The values x that falls within 1 standard deviation of the mean are those which.

|x - 20.4| \leq 7.9

6

|6 - 20.4| = 14.4 > 7.9

6 is not within 1 standard deviation of the mean.

11

|11 - 20.4| = 9.4 > 7.9

11 is not within 1 standard deviation of the mean.

15

|15 - 20.4| = 5.4 < 7.9

15 is within 1 standard deviation of the mean.

17

|17 - 20.4| = 3.4 < 7.9

17 is within 1 standard deviation of the mean.

19

|19 - 20.4| = 1.4 < 7.9

19 is within 1 standard deviation of the mean.

24

|24 - 20.4| = 3.6 < 7.9

24 is within 1 standard deviation of the mean.

25

|25 - 20.4| = 4.6 < 7.9

25 is within 1 standard deviation of the mean.

26

|26 - 20.4| = 5.6 < 7.9

26 is within 1 standard deviation of the mean.

28

|28 - 20.4| = 7.6 < 7.9

28 is within 1 standard deviation of the mean.

33

|33 - 20.4| = 12.6 > 7.9

33 is not within 1 standard deviation of the mean.

3 0
4 years ago
Could you show me how to divide x^3 + 2x^2 + x + 2 by x^2 + 1
DiKsa [7]

Answer:

x+2

Step-by-step explanation:

For this division we can first use factoring of the numerator, then eliminate the common factors.

\frac{x^{3} +2x^{2} +x+2}{x^{2}+1 }

Factoring the numerator by the term grouping method

\frac{x^{2} (x+2)+(x+2) }{x^{2} +1}

\frac{(x^{2} +1)(x+2)}{x^{2} +1}

removed terms

(x+2)

6 0
4 years ago
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