Express 2³a²b in factor form
1 answer:
You might be interested in
Answer:
You should circle:
15, 17, 19, 24, 25, 26, 28
Step-by-step explanation:
The values x that falls within 1 standard deviation of the mean are those which.
6
|6 - 20.4| = 14.4 > 7.9
6 is not within 1 standard deviation of the mean.
11
|11 - 20.4| = 9.4 > 7.9
11 is not within 1 standard deviation of the mean.
15
|15 - 20.4| = 5.4 < 7.9
15 is within 1 standard deviation of the mean.
17
|17 - 20.4| = 3.4 < 7.9
17 is within 1 standard deviation of the mean.
19
|19 - 20.4| = 1.4 < 7.9
19 is within 1 standard deviation of the mean.
24
|24 - 20.4| = 3.6 < 7.9
24 is within 1 standard deviation of the mean.
25
|25 - 20.4| = 4.6 < 7.9
25 is within 1 standard deviation of the mean.
26
|26 - 20.4| = 5.6 < 7.9
26 is within 1 standard deviation of the mean.
28
|28 - 20.4| = 7.6 < 7.9
28 is within 1 standard deviation of the mean.
33
|33 - 20.4| = 12.6 > 7.9
33 is not within 1 standard deviation of the mean.
Answer:
Step-by-step explanation:
For this division we can first use factoring of the numerator, then eliminate the common factors.
Factoring the numerator by the term grouping method
removed terms