X is the number
<span>The sum of two numbers is 11, so other number is : 11 - x
</span><span>The sum of their squares is 65
</span>
x^2 + (11 - x)^2 = 65
x^2 + 121 - 2(x)(11) + x^2 = 65
2x^2 - 22x + 121 = 65
2x^2 - 22x + 121 - 65 = 0
2x^2 - 22x + 56 = 0
2(x^2 - 11x + 28) = 0
2(x - 7)(x -4 ) = 0
x - 7 = 0
x = 7
x - 4 =0
x =4
answer: the numbers are 4 and 7
double check:
<span>sum of two numbers is 11:
4 + 7 = 11
</span><span>The sum of their squares is 65
</span><span>4^2 + 17^2 = 16 + 49 = 65
</span>
Answer:
68
Step-by-step explanation:
Pythagorean theorem: a²+b²=c² a²=32² b²=60² c²=hypotenuse²
32²+60²=c²
1024+3600= c²
4624=c²
Now, take the square root of both sides of the equation to find c
=c
68=c
Answer:
Step-by-step explanation:
Answer:
260,548668 or 260.55 round to the nearest hundreds
Step-by-step explanation:
Area of the trapezoid:
[(major base + minor base)x height]/2
[(22 + 12) x 12]/2 = 204 cm^2
radius = diameter / 2 = 12 / 2 = 6 cm
Area of a semicircle
(radius^2 x pi)/2 = (6^2 x pi)/2 = 56.548668 cm^2
total area = 204 + 56,548668 = 260,548668 cm^2
