Question

Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using

Answer 1

Answer:

$y=\frac{1}{3} x+6$

Step-by-step explanation:

$(3,7)(-6,4)$

Step 1. Find the slope (by using the slope-formula)

m = slope

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{4-7}{-6-3}$

$m=\frac{-3}{-9}$

$m=\frac{3}{9}$

$m=\frac{1}{3}$

Step 2. Write the equation (using the slope and the points)

Here's how to do it:

Slope-intercept Formula $y=mx+b$ whrere m = slope and b = y-intercept

Plug in the slope into the Slope-intercept Formula

$y=\frac{1}{3} x+b$

Find the y-intercept (b) by using a point and substituting their x and y values

$y=\frac{1}{3} x+b$

Point: (3, 7)

$7=\frac{1}{3} (3)+b$

$7=1+b$

$b=7-1$

$b=6$

Step 3. Write the equation in Slope-intercept form

$y=mx+b$

$y=\frac{1}{3} x+6$