<em>Greetings from Brasil...</em>
The average for a set of 9 elements will be
(A + B + C + D + E + F + G + H + I) ÷ 9 = 20
Let's make (A + B + C + D + E + F + G + H + I) like S
<em>(I chose S to remember a sum)</em>
Let us think.....
S ÷ 9 = 20
S = 20 × 9
S = 180
So, (A + B + C + D + E + F + G + H + I) = 180
According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:
<h3>(A + B + C + D + E + F + G + H + I +
J) ÷ 10 = (20 - 4)</h3>
as seen above, (A + B + C + D + E + F + G + H + I) = 180, then
(180 + J) ÷ 10 = 16
(180 + J) = 160
J = 160 - 180
<h2>J = - 20</h2><h2 />
So, including the number - 20 <em>(minus 20)</em> in the original mean we will obtain a new mean whose result will be 16
n would equal <em>-33</em>.
<em>n=-33</em>
Answer:
The solution of the inequality is x ≤ -4. A graph of the solution should have a vertical line passing through x = -4 and be shaded to the left of x = -4
Step-by-step explanation:
-7x + 13 ≥ 41
Subtract 13 from both sides
-7x ≥ 28
Dividing both sides by the -7 changes the inequality sign and we have
x ≤ -4
Hence, the solution of the inequality is x ≤ -4 and the graph of the solution should have a vertical line passing through x = -4 and it should be shaded to the left of x = -4 indicating that only numbers less than or equal to -4 are possible solutions of the inequality.
Hope this Helps!!!
Answer:
#1: -1.5, -0.5, 1/2, 1.5
#2: -3, -1, 1.2, 2.3
Step-by-step explanation:
#1
First we have to figure out the correct order before we plot.
Find the biggest number:
looking at the number the biggest would be 1.5
Find the smallest number:
Looking at the number the smallest would be -1.5
Now that we have that we can easily figure out the rest...
(Going from least to greatest; like on a number line)
-1.5, -0.5, 1/2, 1.5 (That is how you will place the first one)
#2
(Use the steps from above to find the answer)
Biggest: 2.3
Smallest: -3
Order: -3, -1, 1.2, 2.3 (Placing on number line use that order)
Hope this helps :)
It is the last answer letter D 8/3
