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adelina 88 [10]

2 years ago

6

Please help me with this question image attached

2 answers:

user100 [1]2 years ago

3 0

I think the answer is 24

tia_tia [17]2 years ago

3 0

Answer:

The answer is 6 fam :)

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The Pythagorean Theorem ONLY works on which triangle?

ioda

Answer:

right angle ( right )

Step-by-step explanation:

Pythagoras' theorem only works for right-angled triangles, so you can use it to test whether a triangle has a right angle or not. In the triangle above, if a 2 < b 2 + c 2 the angle is acute.

5 0

2 years ago

Read 2 more answers

What is the length of ST? Please explain your answer

Aliun [14]

We know that

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment. (Intersecting Secant-Tangent Theorem)

so

ST²=RT*QT

RT=7 in

QT=23+7-----> 30 in

ST²=7*30-----> 210

ST=√210-----> 14.49 in

the answer is

RT=14.49 in

4 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

What is the answer to this sum 5/6 of 120

ELEN [110]

100 is the correct answer

6 0

3 years ago

-5 5/6 + (-8 4/5)= what show the work

djverab [1.8K]

Answer:

-13 2/3

Step-by-step explanation:

-5 5/6 5x6= 30 4x5= 20

+ 20/30= 2/3

-8 4/5

----------- -5 + -8 = -13

-13 2/3

hope this helps

6 0

3 years ago