All categories

3 years ago

In 2003, the population of an African country was about 22.5 million people, which is 1 million more than

Mathematics

1 answer:

Zepler [3.9K]3 years ago

8 0

Answer:

Population of Africa in 2003 is 22.5 million

population of Africa in 1950 is 1 million - 22.5 million /5

21.5million / 5

21500000/5

4300000

4.3 million people

You might be interested in

Simplify the expression and show your work. 4y+5=-31

kondor19780726 [428]

$4y +5=-31 \\ 
4y+5-5 = 31-5 \\ 
4y=-36 \\ 
4y/4=-36/4 \\ 
y=-9 \\ 
Check: \\ 
4(-9)+5=-31 \\ 
-36+5=-31 \\ 
-31=-31$

3 0

3 years ago

What is the mixed number of 7/4

Nady [450]

7/4 = (4 + 3)/4 = 4/4 + 3/4 = 1 + 3/4 = 1 3/4

$\boxed{\dfrac{7}{3}=1\dfrac{3}{4}}$

5 0

3 years ago

Read 2 more answers

Finding surface area if an triangular prism

SVEN [57.7K]

1)find the area of a triangle. Multiply it by 2 or 4 depending on if they are the same size
2)find the area of the base
3)find the area of the other two sides if you haven’t already.
4) add them all together

8 0

3 years ago

Please help me with the answer to these. The second picture goes along with the first

deff fn [24]

39 cents that would be the answer for your question hopefully

8 0

3 years ago

Consider this right triangle. 21 29 20 Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

The complete question is

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

4 0

3 years ago