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BartSMP [9]
3 years ago
10

Karen wants to buy a $22.50 jacket that is marked 20% off. Select from the drop-down menu to correctly complete the sentence. Th

e best estimate for the discount can be found using the expression?
A. 0.02(20)
B. 0.2(20)
C. 2(20)
D. 20(20)
Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

the discount is 22.5 * .2 =

round 22.5 to 20

20 *.2

Choice B

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A triangle with vertices (−2, 3), (5, 4), and (−1,−1) is translated using the rule (x, y)→(x−3, y+4). What are the coordinates o
kolezko [41]

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(-6,7) (2,8) (-4,3)

Step-by-step explanation:

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3 years ago
At a dinner, the meal cost $22, plus a sales tax of $1.87 was added to the bill, for a total of $23.87. What would the sale tax
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$5.61
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3 years ago
Please help with two and four
bagirrra123 [75]
Question 1)
575 = 100%
57.5= 10%
57.5 × 2= 115 (20%)

question 2)
575=100%
57.5=10%
115=20%
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5.75 × 4=22.8 (4%)

22.8 (4%) + 115 (20%) =137.8(24%) which would be rounded up to 138

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4 0
3 years ago
What is the result when the number 92 is decreased by 50%?
Sliva [168]

Answer:

46

Step-by-step explanation:

50%=0.5

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4 0
3 years ago
A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel
Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

x_{Sh} = x_{o} + v_{Sh}\cdot t

Submarine

x_{Su} = x_{o}+v_{Su}\cdot t

Where:

x_{o} - Position of Diego Garcia island, measured in miles.

x_{Sh}, x_{Su} - Current positions of ship and submarine, measured in miles.

v_{Sh}, v_{Su} - Velocities of ship and submarine, measured in miles per hour.

t - TIme, measured in hours.

If we know that x_{Sh} - x_{Su} = 241\,mi, v_{Sh} = 19\,\frac{mi}{h} and t = 7\,h, then:

x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t

We clear now the velocity of submarine:

\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}

v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}

v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}

v_{Su} = -15.429\,\frac{mi}{h}

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0
3 years ago
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