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BigorU [14]
3 years ago
8

Terminating Decimal between .5 and .6

Mathematics
1 answer:
iragen [17]3 years ago
7 0
A terminating decimal is a number with a finite number of decimals that does not continue endlessly. We'd like to know whether the decimal value obtained by dividing the fraction 5/6 (5 6) is terminating or non-terminating.
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Write a polynomial function with rational coefficients so that P(x)=0 has the given root.
Oxana [17]
(x-7)*(x-12)= x^2-19x+84
4 0
3 years ago
The temperature at 6:00 a.m. was -6°F. By 12 noon, the temperature had increased by 15°F. What was the temperature at
NeTakaya

Answer:

9°

Step-by-step explanation:

-6 + 15 = 9

7 0
3 years ago
The temperature was 68 F .Later that day the temperature was 82 F .How much does the temperature need to rise or fall to return
ruslelena [56]
The answer is A because 82-14=68.
4 0
3 years ago
For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
DaniilM [7]
<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

                        x\neq 1

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1

Hence,

-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

4 0
3 years ago
21. Paul has $900 to invest in a savings account that has an annual interest rate of 1.8%, and a money market account that pays
Iteru [2.4K]

The polynomial that gives the interest earned after a year will have variables, exponents and constants that are joined by operators.

  • The interest earned after one year is <u>0.018·x</u>

Reasons:

The amount Paul has to invest = $900

The annual interest rate from the savings account = 1.8%

The amount the money market account pays per year = 4.2 %

Required: The polynomial for the interest Paul earned by investing <em>x</em> dollars in the savings account.

Solution:

The interest earned is found using the compound interest formula as follows;

\displaystyle A = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t}}

Where;

A = The amount in the account after one year

P = The original amount invested = x

r = The interest rate offered on the investment = 1.8% = 0.018

t = The time of the investment = 1 year

n = The number of times of application of the interest per period = Once per year

Which gives;

Interest = Amount earned = A - P

Therefore;

\displaystyle Interest, \ I  = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t} - P}

Plugging in the values gives;

\displaystyle I  = x \cdot \left(1 + \frac{0.018}{1} \right)^{1 \times 1} - x = x \cdot 1.018^1 - x = 1.018 \cdot x - x = 0.018 \cdot x

The polynomial equation is therefore;

Interest, I = 0.018·x

Using the simple interest formula, we have;

\displaystyle Interest = \mathbf{\frac{P \times r \times t}{100}}

Which gives;

\displaystyle Interest = \frac{x \times 1.8 \times 1}{100}  = 0.018 \cdot x

Interest earned by investing in the savings account for one year, I = 0.018·x

  • The polynomial representing the interest earned is <u><em>I</em></u><u> = 0.018·x</u>

Learn more here:

brainly.com/question/11314161

4 0
2 years ago
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