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3 years ago

The temperature at 6:00 a.m. was -6°F. By 12 noon, the temperature had increased by 15°F. What was the temperature at

Mathematics

1 answer:

NeTakaya3 years ago

7 0

Answer:

9°

Step-by-step explanation:

-6 + 15 = 9

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Someone help me out please!! YOU WILL GET BRAINLIEST

sineoko [7]

nope they are not similar

as in order to say that triangles are similar their sides should be in proportion or angles to be equal but here

here only one angle is equal the other one is not

So they are not similar

8 0

3 years ago

Read 2 more answers

A. Identify all pair of parallel in the diagram.

12345 [234]

Answer:

Parallel: G and F

perpendicular: G & H, F & H

Step-by-step explanation:

G and F are parallel because they will never cross, where as both are perpendicular to H because they intersect at 90°

4 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Michelle and Natalie both went out to eat at a new restaurant. Michelle's bill was $22.50, and she left a 15% tip. Natalie's bil

Sindrei [870]

I personally think Natalie's bill is the greatest because $24.25 × 10 =x

6 0

3 years ago

I nees it asap please

yaroslaw [1]

Answer:

Step-by-step explanation:

Area of a square=L^2

Area=(7a4b8)^2

Area=49a8b16

6 0

3 years ago