Your answer is correct it’s 4/33. You first have to convert the mixed number into an improper fraction. Then you’ll have 1/6/11/8 and then you will simplify the complex fraction. I hope that helps!

4 0

2 years ago

Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height:

$3t=16\implies t=\dfrac{16}3$

b. The particle's velocity is obtained by differentiating its position function:

$\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k$

so that its velocity at time $t=\frac{16}3$ is

$\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k$

c. The tangent to $\vec r(t)$ at $t=\frac{16}3$ is

$\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t$

4 0

2 years ago

Which of the following describes the behavior of the graph shown over the interval (-2,2)?

sergejj [24]

Hello!

We are trying to describe the behavior of the graph given in the question.

To help us understand how to solve this question, we would need to understand concavity.

There are two types of concavity:

Concave up
Concave down

When a graph is concave up, the slope of the line would look like a "U".

When a graph is concave down, the slope of the line would look like a "U" that is flipped upside down.

In this case, we can see that the graph is concave down.

We can tell that the slope is negative due to the fact that the slope is going down, which results in the graph having a negative slope.

We can also tell that the graph is decreasing due to the fact that the line is doing downward.

Answer:

C). negative and decreasing

7 0

1 year ago