Find the value of x. B 10-X 3 D х 2. A С x = [?]

a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no

Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

Solution:

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

Ten years ago he was twice as old as his son

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0

3 years ago

Which statement must be true to prove | || m?

Yakvenalex [24]

Answer C is correct. If angle 1 + angle 2 = 180 degrees then L is parallel to M.
Co interior angles are only supplementary in parallel lines

6 0

3 years ago

Pizza-By-The-Slice sells 7 slices every 10 minutes on average. How many

Dvinal [7]

I think you’re answer is 42 slices of pizza.

the way i worked it out is by finding out how many minutes are in an hour (60 mins). after that i divided it by 10(mins), which would have gotten me 6. therefore i multiplied 7 x 6 which gave me 42.

3 0

2 years ago

Read 2 more answers

A manufacturer of a new medication on the market for Parkinson's disease makes a claim that the medication is effective in 75% o

ale4655 [162]

Answer:

Claim is rejected

Step-by-step explanation:

Solution:-

- The claim was made on the effectiveness of medication on the market of Parkinson's disease to be p = 75%.

- A random sample was taken of N = 150 individuals and n = 100 number of people reported that it was effectively.

- We are to test the claim made by the manufacturer of the medication based on the statistics available for the sample N.

- State the hypothesis for the effectiveness of medication:

Null Hypothesis: p = 0.75 ... Claim

Alternate hypothesis: p < 0.75 .... Test

- The conditions of standard normality:

n*p > 5 , 150*0.75 = 112.5 .. ( Check )

n*(1-p) > 5 , 150*0.25 = 37.5 .. ( Check )

Hence, the standard normal test is applicable. Assuming the population proportion to be normally distributed.

- We will estimate the population proportion with the sample proportion ( p* ):

p* = n / N

p* = 100 / 150

p* = 2/3 = 0.667

- Testing against the claimed population proportion ( p ) = 0.75. The standard normal statistic value is given by:

$Z-test= \frac{(p^* - p)}{\sqrt{p(1-p) / N} } \\\\Z-test= \frac{(0.6667 - 0.75)}{\sqrt{0.75(0.25) / 150} } \\\\Z-test= \frac{-0.0833}{\sqrt{0.00125} } \\\\Z-test= -2.35607 \\$

- We will see whether the Z-test statistic falls in the rejection region defined by the critical value of Z at significance level ( α ) of 0.05.

- The rejection region is defined by the Alternate hypothesis which is less than the claimed value. So, the rejection region defined by the lower tail of the standard normal.

- So for lower tailed test the critical value of statistics is:

P ( Z < Z-critical ) = α = 0.05

Z-critical = - 1.645

- The rejected values all lie to the left of the Z-critical value -1.645

- The claim test value is compared the rejection region:

-2.35607 < -1.645

Z-test < Z-critical

Hence, Null hypothesis rejected because test lies in the rejection region.

Conclusion:

The Null hypothesis or claim made by the manufacturer of Parkinson's disease medication of 75% effectiveness is without sufficient evidence. Hence, the claim made is false or has no statistical evidence.

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%7Bx%7D%5E%7B2%7D%20%2B%204x%20-%205" id="TexFormula1" title="f(x) = {x}^{2}

frutty [35]

The inverse function theorem says

$\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(f^{-1}(16))}$