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hodyreva [135]
3 years ago
10

convert using an equation with an exponent. use your meter strip when its helps you 1,050 millimeters to meters

Mathematics
1 answer:
Vlada [557]3 years ago
6 0
The question requires us to convert 1,050 millimeters into meters. Here we proceed as follows;
10000 mm=1 m
thus the number of meters in 1050 mm will be:
1050/1000
=1.05 m
the answer is 1050mm=1.05 m
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It is 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via Barton
Mashcka [7]
Ask google you can get the answer there
4 0
3 years ago
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At one gym, there is a $12 start-up fee, and after that each month at the gym costs $20. At another gym, it costs $4 to startup,
mart [117]

Answer:

In 4 months the cost of both gyms will be the same.

Step-by-step explanation:

At first we need to model the function to calculate the cost of the 2 gyms.

Slope-intercept equation of linear function

f(x)=mx+b

where

m\rightarrow slope of line

b\rightarrow y-intercept

Let linear function to calculate total cost of gym be:

c(n)=mn+b

where

c\rightarrow total cost of gym

m\rightarrow cost per month (slope)

n\rightarrow number of months

b\rightarrow start-up fee (y-intercept)

For Gym 1

m=20 , b=12

c(n)=20n+12

For Gym 2

m=22 , b=4

c(n)=22n+4

In order to find the number of months the cost of both gyms will be the same, we need to equate both functions and solve for number of months (n)

20n+12=22n+4

\\\textrm{Subtracting 22n from both sides}\\20n-22n+12=22n-22n+4\\-2n+12=4\\\textrm{Subtracting 12 from both sides}\\-2n+12-12=4-12\\-2n=-8\\\textrm{Dividing both sides by -2}\\\frac{-2}{-2}n=\frac{-8}{-2}\\n=4\textrm{ months}

So,

In 4 months the cost of both gyms will be the same.

5 0
4 years ago
5 times what equals 200
KATRIN_1 [288]
200 divided by 5 equals 40.
So therefore, 40 times 5 equals 200.
8 0
4 years ago
Read 2 more answers
Find the product of the complex numbers. Express your answer in trigonometric form. z1 = 5(cos(25) + isin(25)) z2 = 2(cos(80) +
zmey [24]

solution:

Z1 = 5(cos25˚+isin25˚)

Z2  = 2(cos80˚+isin80˚)

Z1.Z2  = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)

Z1.Z2  = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }

Z1.Z2  =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}

(i^2 = -1)

Cos(A+B) = cosAcosB – sinAsinB

Sin(A+B) = sinAcosB + cosAsinB

Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)

 Z1.Z2     = 10(cos105˚+ isin105˚)


5 0
4 years ago
On any given day, the number of users, u, that access a certain website can be represented by the inequality 125-4530
Masteriza [31]

Answer:

Step-by-step explanation:

Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.

Therefore, we now have two inequalities to solve for:

125-u ≤ 30

u-125≤30

For the first one, we can subtract 125 and add u to both sides, resulting in

0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.

The second one can be figured out by adding 125 to both sides, so u ≤ 155.

Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,

u ≥ 95

and

u ≤ 155

combine to be

95 ≤ u ≤ 155, or the 4th option

4 0
3 years ago
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