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hodyreva [135]
3 years ago
10

convert using an equation with an exponent. use your meter strip when its helps you 1,050 millimeters to meters

Mathematics
1 answer:
Vlada [557]3 years ago
6 0
The question requires us to convert 1,050 millimeters into meters. Here we proceed as follows;
10000 mm=1 m
thus the number of meters in 1050 mm will be:
1050/1000
=1.05 m
the answer is 1050mm=1.05 m
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Which of the following graphs shows the solution set for the inequality below?<br> 3|x-3 ≥9
Delicious77 [7]

The graph for the solution set of the absolute value inequality is given at the end of the answer.

<h3>What is the absolute value function?</h3>


The absolute value function is given by:

  • |x| = x, x >= 0.
  • |x| = -x, x < 0.

It measures the distance of a point x to the origin, which is given to x = 0.

In this problem, the inequality is given by:

3|x-3| ≥9

|x-3| ≥ 3

Which means that the distance of x - 3 to the origin is of at least 3 units, hence x - 3 can be:

  • Equal or less to -3.
  • Equal or greater than 3.

Hence:

x - 3 ≤ -3

x ≤ 0

x - 3 ≥ 3

x ≥ 6.

The graph of the inequality is given at the end of the answer.

More can be learned about the absolute value function at brainly.com/question/24734454

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7 0
2 years ago
WILL MARK BRAINLIEST ANSWER IF IT'S ACCORDING TO TOPIC
Sergeu [11.5K]

Answer:

13,10,16, an 11

Step-by-step explanation:

Average = Sum of numbers/# of numbers

The sum is 423

The # of numbers = 50

Sum/# = 423/50, making the average 8.46

The only numbers above 8.46 in the data set are:

13,10,16, an 11

5 0
3 years ago
Could you please find what x=<br><br><br><br>thank you
pickupchik [31]
4x-1=9x-2
Add 1 to both sides
4x= 9x-1
Subtract 9x from both sides
-5x=-1
Divide both sides by -5
X=-1/-5
6 0
3 years ago
How do make a reminder into a fraction
Sedaia [141]
I need an example , more details pls
6 0
3 years ago
Read 2 more answers
3/2 x 4/3 x 5/4… x 2006/2005
Lady_Fox [76]

Answer:

1003

Step-by-step explanation:

The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.

The simplest form of a telescoping producta_{k} \ = \ \displaystyle\frac{t_{k}}{t_{k+1}}, in which the products of <em>n</em> terms is

a_{1} \ \times \ a_{2} \ \times \ a_{3} \ \times \ \cdots \times \ a_{n-1} \ \times \ a_{n} \ = \ \displaystyle\frac{t_{1}}{t_{2}} \ \times \ \displaystyle\frac{t_{2}}{t_{3}} \ \times \ \displaystyle\frac{t_{3}}{t_{4}} \ \times \ \cdots \ \times \ \displaystyle\frac{t_{n-1}}{t_{n}} \ \times \ \displaystyle\frac{t_{n}}{t_{n+1}} \\ \\ \-\hspace{5.55cm} = \ \displaystyle\frac{t_{1}}{t_{n+1}}..

In this particular case, t_{1} \ = \ 2 , t_{2} \ = \ 3, t_{3} \ = \ 4, ..... , in which each term follows a recursive formula of t_{n+1} \ = \ t_{n} \ + \ 1. Therefore,

\displaystyle\frac{t_{2}}{t_{1}} \times \displaystyle\frac{t_{3}}{t_{2}} \times \displaystyle\frac{t_{4}}{t_{3}} \times \cdots \times \displaystyle\frac{t_{n}}{t_{n-1}} \times \displaystyle\frac{t_{n+1}}{t_{n}} \ = \ \displaystyle\frac{3}{2} \times \displaystyle\frac{4}{3} \times \displaystyle\frac{5}{4} \times \cdots \times \displaystyle\frac{2005}{2004} \times \displaystyle\frac{2006}{2005} \\ \\ \-\hspace{5.95cm} = \ \displaystyle\frac{2006}{2} \\ \\ \-\hspace{5.95cm} = 1003

6 0
3 years ago
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