X^2+4xy+4y^2-8x-16y-20

Mathematics

1 answer:

JulsSmile [24]3 years ago

5 0

Answer:

Step-by-step explanation:

x²+4xy+4y²-8x-16y-20=(x+2y)²-8(x+2y)-20

put x+y=t

t²-8t-20=t²-10t+2t-20=t(t-10)+2(t-10)=(t-10)(t+2)

substitute the value of t

x²-4xy+4y²-8x-16y-20=(x+2y-10)(x+2y+2)

i don't know what else you want.

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<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

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<em />

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