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3 years ago

This polygon is a Quadrilateral (4 sided figure). Based on the interior angle sum, find the value of x.

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

Step-by-step explanation:

The total sum of interior angles of a quadilateral is 360°

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Which transformations will produce similar, but not congruent, figures?

kotykmax [81]

Answer: Choice D

The reason why is because any time you have a dilation with a scale factor other than 1, then the resulting figure is either bigger or smaller compared to the original. If two figures of the same shape are different sizes, then they cannot be congruent. The other transformations of rotation, reflection and translation are what we call rigid transformations. They preserve the size leading to keeping the figures congruent.

7 0

3 years ago

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The coordinates of the vertices of triangle ABC are A(1,6), B(2,9), and C(7,10). Identify A'''B'''C''' after the following trans

kipiarov [429]

Answer:

A'''(-1,3), B'''(2,2) and C'''(3,-3)

Step-by-step explanation:

Hello There!

So the first thing we need to do is reflect the coordinates given over the y = x line which would be a straight line across the origin with a rate of change of 1

The rule for a reflection over the y = x line is (x,y) ----> (y,x)

so pretty much we're just flipping the y and x values

(1,6) ---> (6,1)

(2,9) ---> (9,2)

(7,10) ---> (10,7)

so the new coordinates of A'B'C' are A'(6,1) , B'(9,2), and C'(10,7)

Now we want to reflect the points over the x axis

The rule for reflection over the x axis is (x,y) ----> (x,-y)

so the x value stays the same and the y values sign just get flipped so if the y value was originally negative then it will change to positive vise versa

(6,1) ---> (6,-1)

(9,2) ---> (9,-2)

(10,7) ---> (10,-7)

So the coordinates of A''B''C'' are A''(6,-1) , B''(9,-2), and C''(10,-7)

Our final step is to translate 7 units to the left 4 units up

so the rule would be (x,y) ----> (x - 7, y + 4)

6-7=-1 | -1+4=3

(6,-1) ---> (-1,3)

9-7=2 | -2+4=2

(9,-2) ---> (2,2)

10-7=3 | -7+4=-3

(10,-7) ---> (3,-3)

so the after the three transformations the coordinates would be

A'''(-1,3), B'''(2,2) and C'''(3,-3)

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3 years ago

Graph a sine function whose amplitude is 4, period is π , midline is y=−3, and y-intercept is (0, −3). The graph is not a reflec

kupik [55]

Answer:

y=4sin(2x) - 3

Step-by-step explanation:

Recall the form of a sinusoidal function is Asin(Bx + C) + D, where A is the amplitude, B is the frequency (could also be viewed as the period), C is the horizontal (phase) shift, and D is the vertical shift. Also, recall sin(x) has a period of 2π.

You start with the parent function (sin(x)).

Then, knowing the amplitude is 4: 4sin(Bx + C) + D

Then, knowing the period of the regular sine function is 2π, to get to a period of π, divide by 2 (the period of the curve changes by a factor of 1/2), so your B coefficient is 2: 4sin(2x + C) + D

There is no phase shift, so omit C: 4sin(2x) + D

Since the midline is y = -3, that is your vertical shift (D): 4sin(2x) - 3

Graph of y = 4sin(2x) - 3 is below:

3 0

3 years ago

Why is the gfc of any two numbers is always even

Sati [7]

There's no "why" because it isn't.

The greatest common factor of two numbers
is only even when the two numbers are even.

==> The greatest common factor of '14' and '21' is ' 7 ' .

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3 years ago

This is a precalculus problem on complex numbers. Please give a explanation with your answer, thank you.

Ulleksa [173]

$z = \stackrel{x}{-2}\stackrel{y}{-5} i\qquad \begin{cases} \theta =tan^{-1}\left( \frac{y}{x} \right)\\\\ \theta =tan^{-1}\left( \frac{-5}{-2} \right)\\\\ \theta \approx 1.19~radians \end{cases}$

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2 years ago

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