Answer:
9.
Step-by-step explanation:
We have been given that dimensions of original photo are 4 inches by 6 inches. We want the photo on the poster to be of dimensions 3 feet by 4 1/2 feet.
First of all we will convert dimensions of poster from feet to inches.

Now let us compare sides of our original photo with corresponding sides of poster.
Now let us compare the second pair of corresponding sides.

We have seen that sides of poster are 9 times the sides of our original photo, therefore, the scale factor of this dilation is 9.
Answer:
4/5*reciprocal of -2/10
The reciprocal of -2/10 is 10/-2
4/5*10/2
Cancelling the numbers
-4 is the answer
Step-by-step explanation:
I hope it will help you :)
I think the answer is B because that is the only answer that could make sense.
Answer:
80 pages
Step-by-step explanation:
3/4=60/80
✰ <u>Concept</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>
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In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.
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✰ <u>Given</u><u> </u><u>Information</u><u> </u>:-
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- Hypotenuse = 22 ft.
- Base = 10 ft.
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✰ <u>To Find</u><u> </u><u>:</u><u>-</u>
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- The value of side or the perpendicular
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✰ <u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>
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
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✰ <u>Solution</u><u> </u><u>:</u><u>-</u>
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
Thus, option B. 19.60 ft. is the correct option.
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