Answer: D. 7^11
Reason:
The rule we use is ![a^b*a^c = a^{b+c}](https://tex.z-dn.net/?f=a%5Eb%2Aa%5Ec%20%3D%20a%5E%7Bb%2Bc%7D)
When multiplying exponentials of the same base, we add the exponents.
The exponents 5 and 6 add to 5+6 = 11
So,
![7^5 \times 7^6 = 7^{5+6} = 7^{11}](https://tex.z-dn.net/?f=7%5E5%20%5Ctimes%207%5E6%20%3D%207%5E%7B5%2B6%7D%20%3D%207%5E%7B11%7D)
The base stays the same the entire time.
Answer:
1. (a-c)
+ b![\sqrt{y}](https://tex.z-dn.net/?f=%5Csqrt%7By%7D)
2. 9m + 2![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
3. 6a
4. (5a - 3b)![\sqrt{5y}](https://tex.z-dn.net/?f=%5Csqrt%7B5y%7D)
Step-by-step explanation:
1. since a and c share the same squareroot x, you can combine these together.
2. First add like terms together. 4m - m + 6m = 9m. Then 5
and -3
combined equals 2![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a
4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:
5a
- 3b![\sqrt{5y}](https://tex.z-dn.net/?f=%5Csqrt%7B5y%7D)
We can combine the two like terms and get the final answer above.
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Answer:
2%
Step-by-step explanation:
After 4 cards are drawn at random, that leaves 48 cards. 1 divided by 48 is .0208.
Hence, 2%
Okay so first you want to simplify the given equation (7x+3y)(7x-3y)
in order to do this you multiply the first number of the first equation (7x) with the first number of the second equation (7x) this gives you 49x^2
Now you want to multiply the second number of the first equation (3y) by the second number of the second equation (-3y) this gives you -9y^2
Its as easy as pie!