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Fynjy0 [20]
1 year ago
15

What’s the volume of the sphere

Mathematics
1 answer:
vodka [1.7K]1 year ago
3 0

Answer:

\pi(r^{2}h)

Step-by-step explanation:

r = radius

h = height

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Rewrite 9cos 4x in terms of cos x.
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\bf \qquad \textit{Quad identities}\\\\
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\begin{cases}
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9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
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72cos^4(x)-72cos^2(x)+9


---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
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\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[  \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
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2\left[  \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
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\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}
4 0
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Answer:

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11/22=5/x [Theorem]

1/2=5/x

x=10

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How will the volume of the pyramid change if each side is multiplied by a factor of .5
kupik [55]
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Elevando um certo numero natural,maior do que zero,ao expoente 101 encontrarmos como resposta 1. Qual é esss numero? 101 A) 0 B)
Feliz [49]

Answer:

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Step-by-step explanation:

The computation of the number is shown below:

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Like

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5 0
3 years ago
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