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Elis [28]
2 years ago
8

PLEASE HELP ASAP :))

Mathematics
1 answer:
Firlakuza [10]2 years ago
8 0
No, Sophie made a mistake going from Step 3 to Step 4.

Explanation:
Using PEMDAS, or the order of operations, Sophie should have finished multiplying before adding. Here’s how her expression should’ve ended:

= 18 + 7 • 6
= 18 + 42
= 60
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TV=3x-24 and VX=2x+1. What is the value of VX?<br> 1. 25<br> 2. 99<br> 3. 5<br> 4. 51
Maslowich
ΔTXV is an <span>isosceles triangle because ∡T = ∡X therefore TV = VX.

3x - 24 = 2x + 1    |subtract 2x from both sides

x - 24 = 1    |add 24 to both sides

x = 25
</span>
7 0
2 years ago
Read 2 more answers
Write an equivalent expression for (3m - 6)(8m2 - 40m - 5).​
ycow [4]

Answer:

24m3−168m2+225m+30

Step-by-step explanation:

(3m+−6)(8m2+−40m+−5)

=(3m)(8m2)+(3m)(−40m)+(3m)(−5)+(−6)(8m2)+(−6)(−40m)+(−6)(−5)

=24m3−120m2−15m−48m2+240m+30

=24m3−168m2+225m+30

4 0
3 years ago
688×29=<br>how to do this step by stwp
laila [671]

688

x 29

  6192  

1376 x  

19952


So you start by taking 9 from 29 and multiplying it by 688. when you get the answer put it below the line. then multiply the 2 from the 29 and whne you get the answer put a zero on the end and then add the answer you got from 9x688  (6192) and 2x688 (13760) and then thats youre answer. hope it helps!

8 0
3 years ago
An old road was 3.95 miles long. After a renovation it was 3.81 times as long. How long was the road after the renovation?
guapka [62]
3.95 × 3.81 = 15.0485

The road was 15.0485 miles long after the renovation.

Hope this helps!
4 0
3 years ago
Exercise 1.A committee of five people is chosen randomly from four men and six women. Find the probability that:a) Exactly four
MatroZZZ [7]

Answer with explanation:

Given : Number of men = 4

Number of women = 6

Total people = 6+4=10

Total number of ways to make a committee of five people from 10 persons :-

^{10}C_{4}=\dfrac{10!}{4!(10-4)!}=210

a) Number of ways to make committee that has exactly four women :

^6C_4\times ^4C_1=\dfrac{6!}{4!(6-4)!}\times4=60

The  probability that committee has exactly four women :

\dfrac{60}{210}=\dfrac{2}{7}

b) Number of ways to make committee that has at-least four women :

^6C_4\times ^4C_1+^6C_5=\dfrac{6!}{4!(6-4)!}\times4+6=66

The probability that committee at-least four women :

\dfrac{66}{210}=\dfrac{22}{70}

c) Number of ways that committee has more than 4 women :-

^6C_5\times^4C_0=6

The probability that committee has more than 4 women :-

\dfrac{6}{210}

Now, the  probability that committee has at most four women :-

1-\dfrac{6}{210}=\dfrac{204}{210}=\dfrac{102}{105}

5 0
3 years ago
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