Answer:
<h3>1) 5(7
- x + 8)</h3>
first box: 5 * 7 = 35
35 x^2
second box: 5 * -1 = -5
-5x
third box: 5 * 8 = 40
40
answer: 35 - 5x + 40
<h3>2) 2x(4x^2 + 3x + 6)</h3>
first box: 2x * 4x^2
2 * 4 = 8
x * x^2 = x^3
8x^3
second box: 2x * 3x
2 * 3 = 6
x * x = x^2
6x^2
third box: 2x * 6
2 * 6 = 12
12x
answer: 8x^3 + 6x^2 + 12x
<h3>
3) (tp + 5)(4p - 6)</h3>
top left box: tp * 4p
p * p = p^2
4t
top right box: tp * - 6
-6tp
bottom left box: 5 * 4p
5 * 4 = 20
20p
bottom right box: 5 * - 6
5 * -6 = -11
-11
answer: 4tp^2 - 6tp + 20p - 11
<h3>
4) (4a - 8)(8a - 1)</h3>
top left box: 4a * 8a
4 * 8 = 32
a * a = a^2
32a^2
top right box: 4a * -1
4 * -1 = -4
-4a
bottom left box: -8 * 8a
-8 * 8 = -64
-64a
bottom right box: -8 * - 1
-8 * - 1 = 8
8
32a^2 - 4a - 64a + 8
<em>combine like terms</em>
32a^2 - 68a + 8 = answer
Answer:
45
Step-by-step explanation:
Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.
m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1
The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.
m(arc)EVL + m(arc)EHL = 360
m(arc)EVL = 360 - m(arc)EHL Eq. 2
We are given this:
m<EYL = (1/3)m(arc)EHL Eq. 3
Substitute equations 2 and 3 into equation 1.
(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]
Now we have a single unknown, m(arc)EHL, so we solve for it.
2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]
2m(arc)EHL = 1080 - 6m(arc)EHL
8m(arc)EHL = 1080
m(arc)EHL = 135
Substitute the arc measure just found in Equation 3.
m<EYL = (1/3)m(arc)EHL
m<EYL = (1/3)(135)
m<EYL = 45
Answer:
Perimeter= 49
area= 360
Step-by-step explanation:
perimeter means you need to add 40+9 and area means you must multiple the numbers.
The appropriate choice is ...
... D) 1.0×10⁻³ inch
